# Solve the equation: 1.2e^(-5x)+2.6=3?

I am about to flunk Algebra Two and I really need help. This is one of the problems. If you could help me I would be really happy.Thank You.

The equation is: 1.2e^(-5x)+2.6=3

This chapter is about Expoential and Logarithmic equations.

I forgot to say I need to know detailed steps to solve it, just not the answer please!

I need the steps in words. I dont know what you did with just numbers. but thanks so far tho!

### 6 Answers

- Paschal HLv 61 decade agoBest Answer
1.2e^(-5x)+2.6=3

1.2e^(-5x) = .4

e^(-5x) = .4/1.2 = 1/3

1/[e^(5x)] = 1/3

e^(5x) = 1/3

5x = ln(1/3)

x = [ln(1/3)]/5

- 3 years ago
technique A: 5X = a hundred and fifty five 5 x X = a hundred and fifty five X = a hundred and fifty five/5 X = 31 OR technique B: 5X = a hundred and fifty five 5 x X = a hundred and fifty five 5 = a hundred and fifty five/X X = a hundred and fifty five/5 X = 31 the suggestions-blowing technique is way less complicated, however the backside is likewise in theory suggestions-blowing. In tests, the suggestions-blowing technique is the appropriate to apply. desire this enables!

- 1 decade ago
I'm assuming you may want the solution panned out into a more complicated form?

First you should isolate your operator.

Subtract 2.6 from both sides.

Divide both sides by 1.2

Then take ln of both sides

Now you have -5x=ln1/3

Dvide both sides by -5.

You'll have to use a calculator for parts of this problem...

the resulting solution is a decimal.. 0.219722..

Divide by -5 to isolate your variable.

- shadowca1964Lv 41 decade ago
1. subtract 2.6 from both sides

1.2e^(-5x) = .4

2. divide both sides by 1.2

e^(-5x) = (1/3)

3. to clear the e take the ln of both sides

ln (e^(-5x)) = ln(1/3)

-5x= ln(1/3) or -5x = - ln(3)

answer x=(1/5)ln(3)

I used the following laws:

ln (e^(a))=a

ln(1/a) = ln(a^(-1)) = -ln(a)

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