i'm so confused when it comes to these stoichiometry problems. can anyone please help with this problem, definite 10 points to most help thanks-

Given: H2SO4 + NaOH ---> Na2SO4 + HOH(unbalanced)

it says to balance the equation first

a) if 20.0 grams of H2SO4 and 20.0 grams of NaOH are reacted, how many grams of Na2SO4 will be produced?

thanks a lot!

Relevance

Hi fizz,

look at it this way: the left-hand side (LHS) of the equation

has 3 H, 1 S, 5 O and 1 Na. The right-hand side (RHS) of the equation has 2 Na, 1 S, 5 O and 2 H.

so the first action you need would be to multiply the NaOH on the LHS by 2 (since you need at least 2 Na).

This would then give you: 4H, 1S, 6O, 2Na. (on LHS)

next you would need to multiply the H2O on the RHS by 2 to get a balance of the number of Os and Hs.

This gives you: 2Na, 1S, 6O, 4H. (RHS)

after this you would notice that LHS = RHS, right?

You then would have the basic equation. Now be wary that the equation is basically saying

1 mole of H2SO4 reacting with 2 moles of NaOH will give you 1 mole of Na2SO4 and 2 moles of H2O.

Moles and grams are not equitable. I leave it up to you to work out the relationship of moles to grams (this should be part of your standard definition training) you will need this before you can calculate how much Na2SO4 will be produced.

• Anonymous

h2so4 + 2naoh gives na2so4 + 2 hoh

each atom must balance on each side, so by using 2 molecules of naoh it gives you 2 of hoh (h2o) and balances the na2 on the right hand side of the equation.

that is ---- 4 hydrogen, 1 sulphur, 6 oxygen, and 2 sodium (na) on each side of the equation ---- easy really,hope it helps.

part 2 ---- as two molecules of naoh is needed for a balanced equation, only half of the h2so4 will be reacted. so you will make 30 grams of na2so4 and have 10 grams of unreacted h2so4. ( i think )

• redick
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3 years ago

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