Anonymous

# Write the equation of the line that is perpendicular to the line 2x - 3y = 6 and passes through the point (1,2

Write the equation of the line that is perpendicular to the line 2x - 3y = 6 and passes through the point (1,2).

Relevance

perpendicular lines have an inverse slope and with the opposite sign. In the formula y = mx + b, the m is the slope, so solve your equation for y:

2x - 3y = 6

-3y = 6 - 2x

y = (6 - 2x)/-3

y = (2/3) x - 2

the slope here is 2/3

now you need a line that have a slope -3/2 and pass through the point (1,2)

so you can use the formula of:

y = mx + b

the value of:

m = -3/2

x = 1

y = 2

solve for b:

y - mx = b

2 - (-3/2)(1) = b

2 + 3/2 = b

b = 7/2

now you know that the "y intersection" will be in 7/2, that is a point of the line

so that point will be (0,7/2) or (0,3.5) which is the same

so the equation would be:

y = (-3/2)x + 7/2

you can find more about slope in

• Y = -3/2x + 7/2

• Solve for y.... when you get the slope just do the opposite ov it... n then plug in the points given and the slope into y-y1=m(x-x1) itzz very easy...try it...

• slope is -3/2, y-2=(-3/2)(x-1)