Anonymous
Anonymous asked in Science & MathematicsMathematics · 1 decade ago

Write the equation of the line that is perpendicular to the line 2x - 3y = 6 and passes through the point (1,2

Write the equation of the line that is perpendicular to the line 2x - 3y = 6 and passes through the point (1,2).

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  • 1 decade ago
    Best Answer

    perpendicular lines have an inverse slope and with the opposite sign. In the formula y = mx + b, the m is the slope, so solve your equation for y:

    2x - 3y = 6

    -3y = 6 - 2x

    y = (6 - 2x)/-3

    y = (2/3) x - 2

    the slope here is 2/3

    now you need a line that have a slope -3/2 and pass through the point (1,2)

    so you can use the formula of:

    y = mx + b

    the value of:

    m = -3/2

    x = 1

    y = 2

    solve for b:

    y - mx = b

    2 - (-3/2)(1) = b

    2 + 3/2 = b

    b = 7/2

    now you know that the "y intersection" will be in 7/2, that is a point of the line

    so that point will be (0,7/2) or (0,3.5) which is the same

    so the equation would be:

    y = (-3/2)x + 7/2

    you can find more about slope in

  • 1 decade ago

    Y = -3/2x + 7/2

  • 1 decade ago

    Solve for y.... when you get the slope just do the opposite ov it... n then plug in the points given and the slope into y-y1=m(x-x1) itzz very easy...try it...

  • ?
    Lv 7
    1 decade ago

    slope is -3/2, y-2=(-3/2)(x-1)

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  • Anonymous
    1 decade ago

    do it your self

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