# A rectangle has a length pf x . Its width is 3 feet longer than twice the length. Find the dimensions if its a

A rectangle has a length pf x . Its width is 3 feet longer than twice the length. Find the dimensions if its area is 80ft².

(round to the nearst 1/10 )

Length be x

Then width is 2x + 3

Area = Length x Width = 80ft.

80 = x (2x + 3)

= 2x² + 3x

descibe the rest as in qudratic formula

(round to the nearst 1/10 )

Length be x

Then width is 2x + 3

Area = Length x Width = 80ft.

80 = x (2x + 3)

= 2x² + 3x

descibe the rest as in qudratic formula

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