# A rectangle has a length pf x . Its width is 3 feet longer than twice the length. Find the dimensions if its a

A rectangle has a length pf x . Its width is 3 feet longer than twice the length. Find the dimensions if its area is 80ft².

(round to the nearst 1/10 )

### 2 Answers

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- 1 decade agoBest Answer
width = 2x +3

length = x

Area = length * width

80 = x(2x+3)

i think you can do the rest.. hehehe

- 1 decade ago
Length be x

Then width is 2x + 3

Area = Length x Width = 80ft.

80 = x (2x + 3)

= 2x² + 3x

Solving

2x² +3x - 80 = 0

x =5.6ft

So length = 5.6 ft

and width = 14.2 ft

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