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# Can you help me find the first and second derivative?

C(u) = (k+((c)(lambda)(u))) / (1 - e^-(alpha)(u))

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- cidyahLv 71 decade agoFavorite Answer
Use the Quotient Rule.

= [1-e^(-alpha(u)] [k+(c)(lamba)] - [k+(c)(lamda)(u)) (-e^(-alpha(u)) (-alpha)] / (1-e^(-alpha)(u)]^2

Note:

if f(x) = h(x)/g(x)

f'(x) = [g(x) h'(x) - h(x) g'(x)] / [g(x)]^2

here h(x)=(k+((c)(lambda)(u)))

g(x)=(1 - e^-(alpha)(u))

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