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# 微積分級限問題

lim(n→∞) 分子Σ(k=1~n) n^a(n+k)^b 分母Σ(k=1~n) n^b(n+k)^a

a>0,b>0

因為是分數不好打上去所以分子跟分母的地方分開打

分子: n的a次方臣上n+k的b次方

分母: n的b次方臣上n+k的a次方

### 2 Answers

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- densityLv 61 decade agoFavorite Answer
Hint: Using the definition of Riemann sum.

2008-02-16 02:49:47 補充：

We use the definition of Riemann sum to slove it!

Source(s): myself

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