# How much ice (in grams) would have to melt to lower the temperature of 355 mL of water from 26 C to 6 C?

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Assume a density of water of 1.0 g/mL

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The heat of fusion of ice is about 80 cal/gram

You want to lower 355 ml (cc) by 20 Celsius degrees which is one calorie per gram (ml or cc) per degree.

You therefore need 355*20 = 7100 calories to lower the temperature of the water.

One gram of ice will give you 80 calories so you will need 88.75 grams of ice assuming the temperature of the ice is 0 degrees C

You want to lower 355 ml (cc) by 20 Celsius degrees which is one calorie per gram (ml or cc) per degree.

You therefore need 355*20 = 7100 calories to lower the temperature of the water.

One gram of ice will give you 80 calories so you will need 88.75 grams of ice assuming the temperature of the ice is 0 degrees C

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