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A spring form a car suspension has a spring constant of 4.5 × 104 N m-1. How much

energy must be transferred to the spring to compress it from its natural length of 0.32 m

to a length of 0.23 m?

1 Answer

  • 1 decade ago
    Favorite Answer

    By Hooke's law, the elastic energy stored in a stretched/compressed spring is kx2/2 where k and x are the spring constant and amount of compression/stretch respectively.

    Therefore from 0.32 m to 0.23 m, compression = 0.09 m

    So, energy transferred is:

    (4.5 × 104 × 0.092)/2 = 364.5 J

    Source(s): My physics knowledge
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