Yahoo Answers is shutting down on May 4th, 2021 (Eastern Time) and the Yahoo Answers website is now in read-only mode. There will be no changes to other Yahoo properties or services, or your Yahoo account. You can find more information about the Yahoo Answers shutdown and how to download your data on this help page.
A spring form a car suspension has a spring constant of 4.5 × 104 N m-1. How much
energy must be transferred to the spring to compress it from its natural length of 0.32 m
to a length of 0.23 m?
- 魏王將張遼Lv 71 decade agoFavorite Answer
By Hooke's law, the elastic energy stored in a stretched/compressed spring is kx2/2 where k and x are the spring constant and amount of compression/stretch respectively.
Therefore from 0.32 m to 0.23 m, compression = 0.09 m
So, energy transferred is:
(4.5 × 104 × 0.092)/2 = 364.5 JSource(s): My physics knowledge