# What is the probability that you will NOT draw a queen from a deck of 52 cards, if you are to draw 4 cards?

if 4 cards are chosen randomly froma deck of 52 cards, there are 270,725 difference combinations. what do you think the probability is that out of these sets of 4 cards, you will NOT get a queen

Update:
the chances of getting 4 aces, are...
1 x 1 x 1 x 1 / 270,725.
there are 4 queens in the deck of cards, is it logical to say that..... if the chances of getting 4 queens in one draw are 1 / 270,725 that the chances of NOT drawing this combination would be 270,724. But that wouldn't make sense because you can...
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the chances of getting 4 aces, are...

1 x 1 x 1 x 1 / 270,725.

there are 4 queens in the deck of cards, is it logical to say that..... if the chances of getting 4 queens in one draw are 1 / 270,725 that the chances of NOT drawing this combination would be 270,724. But that wouldn't make sense because you can get King, King, King, Queen. 3 Kings, 1 queen. tough question..

1 x 1 x 1 x 1 / 270,725.

there are 4 queens in the deck of cards, is it logical to say that..... if the chances of getting 4 queens in one draw are 1 / 270,725 that the chances of NOT drawing this combination would be 270,724. But that wouldn't make sense because you can get King, King, King, Queen. 3 Kings, 1 queen. tough question..

Update 2:
the correct answer has been established.

(48/52)*(47/51)*(46/50)*(45/49) = 38916/54145

or a 71.87 percent chance.

(48/52)*(47/51)*(46/50)*(45/49) = 38916/54145

or a 71.87 percent chance.

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