Anonymous
Anonymous asked in Science & MathematicsMathematics · 1 decade ago

Rectangles B and C are attached to rectangle A,. The area of rectangle B is 2t^2 - 3t + 1. The area pf rectang

rectangle C is 3t^2-2t-1. The lenghts of these two rectangles are as shown(B = 2t -1 and C = 3t+1)

a)Write a rational expression that represents the width of rectangle B

b)Write a rational expression that represents the width of rectangle C.

c)Write and simplify the product of the expressions you wrote in parts a) and b)

d)What type of rectangle is A?Explain

4 Answers

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  • sv
    Lv 7
    1 decade ago
    Best Answer

    Rectangles B and C are attached to rectangle A,. The area of rectangle B is 2t^2 - 3t + 1. The area pf rectang

    rectangle C is 3t^2-2t-1. The lenghts of these two rectangles are as shown(B = 2t -1 and C = 3t+1)

    a)Write a rational expression that represents the width of rectangle B = (2t^2 - 3t + 1) / (2t -1) = (t -- 1)

    b)Write a rational expression that represents the width of rectangle C = (3t^2-2t-1) / (3t+1) = (t -- 1)

    c)Write and simplify the product of the expressions you wrote in parts a) and b) = (t -- 1)(t -- 1) = t^2 -- 2t + 1

    d)What type of rectangle is A?Explain : A is sandwiched by rectangles B and C on either side of it so that the three are in a row of width (t -- 1).

  • 1 decade ago

    Well for the first two you just have to factorise the quadratics..

    Rect B = (2t-1)(t-1)

    Rect C = (3t+1)(t-1)

    A. t-1

    B. t-1

    C. see above

    D. if connected to the widths of B & C then A is a square... because it is a rectangle with the same side lengths.

    Eugene

  • 1 decade ago

    S=L.W ( Area = Lenght . Width )

    so :

    A)

    2t^2 -3t+1 = ( 2t-1 ).p(t)

    Width B = p(t) = ( 2t^2 -3t +1)/( 2t-1 ) = t - 1

    B)

    like A) :

    Width C = ( 3t^2 -2t-1)/( 3t+1) = t -1

    C)

    (t-1)(t-1) = t^2 -2t +1

    D)

    square

  • 3 years ago

    a) area = length x width, so for rectangle A, we divide the area via the prevalent length of 2x+a million to get the width of the different component; this quotient is 3x+a million b) in addition, divide the area of B via 2x+a million to get 2x-3 c) width of B - width of A = (2x-3)-(3x+a million)=-x-4 d) width of A - width of B = (3x+a million)-(2x-3)=x+4 e) they're of direction negatives of one yet another considering that they have been produced via reversing order of subtraction

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