疑問 - 如何使用C寫一個猜英文單字的遊戲?

Question

以前常玩的猜字母遊戲@@

老師會話一個人上吊的圖~~~

然後26個字母 去猜一個單子~~~

不過要寫程一個遊戲 我覺得好難阿

誰可以幫幫我

1.The computer randomly selects an English word from a list of at least 10 English words.

2.The computer randomly exposes some characters of an English word of the lenght n. At least 1 character is exposed and at maximum n - 1 character.

3.The player guesses character by character until the word is solved or the 8 times of wrong guesses is exceeded.

4.Each time a correct character is guessed the character is exposed.

5.They player can decide to continue to play or not.

Hint:

1.To get the string length, use the strlen function.

2.To compare two strings, use the strcmp function.

3.To count the number of strings, refer to the following code:

main() {

char *words[] = {"computer", "information", "engineering", "programming"};

char guess[30];

int i, n = sizeof(words)/sizeof(char *);

printf("List of string: ");

for (i = 0; i < n; i++) printf("%s ", words[i]);

i = rand() % n;

printf("\nEnter your guess : ");

scanf("%s", guess);

printf("Your guess is \"%s\".\n", guess);

printf("Computer selects \"%s\".\n", words[i]);

if (strcmp(guess, words[i])) printf("Your guess is wrong.\n");

else printf("Your guess is correct.\n");

}

A possible session could look like as follows:

The word to guess: -a--c

Your guess => o

The word to guess: -a--c

Your guess => m

The word to guess: ma--c

Your guess => l

The word to guess: ma--c

Your guess => g

The word to guess: mag-c

Your guess => i

Correct! The word is magic.

====================================================

Continue (Y/N)? Y

The word to guess: wo--e-

...

...

You guessed wrong more than 8 times. The word is wonder.

====================================================

Continue (Y/N)? N

Bye!

拜託一下了

Answer 1

Favorite Answer

示範程式 與 示範執行 差好多喔！

哪位天才老師給的啊！？

#include <conio.h>

#include <ctype.h>

#include <stdio.h>

#include <stdlib.h>

#include <string.h>

#include <time.h>

#define MAX 32

#define MAXG 8 // Maximun guessing times

int main()

{ char *words[] = {"computer", "information", "engineering", "programming",

"test", "about", "an", "IBM", "Microsoft", "Visual", "Studio" },

word[MAX],

ch;

int g, i, l, m, n = sizeof(words)/sizeof(*words), w;

srand((unsigned) time(NULL));

do

{ w = rand() % n;

strcpy(word, words[w]);

l = (int) strlen(word);

do

{ for (m=i=0; i<l; i++)

if (rand() > 3*(RAND_MAX>>2))

word[i] = '-', m++;

} while (!m); // no character is gone

if (m == l) // all the characters are gone

continue; // choice a new word because this word maybe bad!

for (g=0; word[g]!='-'; g++);

for (i=MAXG; i && m; i--)

{ printf("The word to guess: %s\nEnter your guess: ", word);

printf("%c\n", ch = (char) getch());

if (ch == words[w][g])

{ word[g] = ch, m--;

for (; word[g]!='-'; g++);

} }

if (strcmp(word, words[w]))

printf("You guess more than %d times.\nThe word is %s.", MAXG, words[w]);

else

printf("Your guess is correct!");

printf("\n=================================\nAgain? (Y/N)\b\b\b\b");

} while (toupper(getchar()) != 'N') ;

printf("Bye!\n");

return 0;

}

你試玩看看囉！

Answer 2

不難，先建立一個文件檔裡面放滿英文單字

接著使用讀檔的方式把讀進指標中，然後隨機抽取英文單字，再把字串隨機排序，在顯示出來，讓人去猜就好了