How high vertically does a .3 kg block rise if the spring is compressed .08 m?
A 0.300 kg block on a vertical spring with a spring constant of 5.00 103 N/m is pushed downward, compressing the spring 0.080 m. When released, the block leaves the spring and travels upward vertically. How high does it rise above the point of release? In meters
- kuiperbelt2003Lv 71 decade agoFavorite Answer
This is a problem best addressed by using conservation of energy methods. At first, the block only has potential energy due to the compression of the spring, since it is not yet moving it has no kinetic energy. When it is at its highest point, it is momentarily stationary, and has no kinetic energy. At its highest point, it has converted all the energy of compression into potential energy of height. You can write this as:
PE compression = PE height, or:
1/2 kx^2 = mgh
The mass is 0.3kg, the distance of compression (the x on the left hand side) is 0.08m, k is the spring constant, g is the accel of gravity (9.8 m/s/s) and h is the unknown, the height to which it rises.
I am not sure what value of k you are posting, whether it is 5 N/m, 5.00103 N/m (not likely), or 103 N/m. Whatever is the correct value of k, just plug it into the equation above with the other data and solve for h. Hope this helps.
- 1 decade ago
physics is over for me......thank god....Source(s): cramster.com