Algebra help please?

Simplify. (x^2 + 11x + 28) divided by (x^2 – 8x - 48)

a. ( x – 7) divided by (x + 12)

b. ( x - 7) divided by (x - 12)

c. ( x + 7) divided by (x + 12)

d. ( x + 7) divided by (x - 12)

Simplify. (5y^2/4) times (20x/10y)

a. 5x/2

b. (xy^2)/2

c. 10xy

d. (5xy)/2

4 Answers

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  • Anonymous
    1 decade ago
    Favorite Answer

    factor the terms

    (x+7)(x+4)

    --------------

    (x-12)(x+4)

    The (x+4) terms cancel each other and you are left with

    (x+7)/(x-12)

    For the second one:

    When you multiple the terms you should get:

    100xy^2

    ------------

    40y

    Cancel the y terms and get:

    100xy

    --------

    40

    Simplify:

    5xy

    -----

    2

  • 1 decade ago

    First one: The numerator is factored to (x+7)(x+4)

    The denominator is factored to (x+4)(x-12).

    Now you have (x+7)(x+4)/(x-12)(x+4).

    The x+4's cancel each other out, and you are left with (x+7) divided by (x-12).

    the answer is d.

    Second one: Multiply the numerators together (5y^2)(20x)= 100xy^2

    Multiply the denominators together = 40y

    Now you have 100xy^2/40y.

    The y is in the denominator cancels out one of the y's in the numerator. 100/40 = 10/4 = 5/2. You are left with 5yx/2. The answer is d.

    If you are having trouble in math, please see your teacher. Math builds on itself and if you are having trouble with these, you will be totally confused when your teacher goes to the next topic.

  • 1 decade ago

    you have to factor them for the 1st problem

    (x^2 + 11x + 28)

    ----------------------

    (x^2 - 8x - 48)

    =

    (x+7) (x+4)

    ---------------

    (x-12) (x+4)

    = (x+7) / (x-12) d.

    #2.

    5y^2 ...... 20x

    ------- * ----------

    4 .......... 10y

    = y * 5x / 2 = 5xy/2 d.

  • 1 decade ago

    (x+4)(x+7)

    -----------------------------

    (x-12)(x+4)

    d. x+7/x-12

    5y^2/4 * 20x/10y

    y * 5x/2= 5xy/2 d.

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