## Trending News

# Can you help me with some Algebra problems?

1. Graph the linear system and tell how many solutions it has.

2x-y=5

-x+y=-3

2x-3y=-6

-3y+2x=3

3x+y=1

2y=2-6x

Find x and y by using algebraic method.

3x-2y=10

5x+3y=-15

3x-5y+10=0

-9x+15y=-30

2x-4y=-6

-2x+4y=6

Find x, y, and z.

-3x+4y=-6

5x-3z=-22

3y+2z=-1

Please Help THANKS!!

### 3 Answers

- momLv 71 decade agoFavorite Answer
For graphing, I like to let first x then y =0, and find the corresponding point. If it's a fraction, I like to use the slope-intercept method.

1. second one, x=0,y=-3 and y=0, x=3

first one, y=2x-5, x=0, y=-5 and pick a value for x, find the corresponding y OR start at the intercept and go up 2, to the right 1

2. x=0, y=1, now let x=any number , say 3, y= -8

second one; x=0, y=-1, and for the second point, solve for y (this might be easier to do for all the equations)

-3y=-2x +3. so y= 2/3 x -1

pick an x value that is divisible by 2 so you won't have fractions. Let x=3, y= 1

3. y=-3x+1 x=0,y=1 and x=1. y=-2

the second is also y=-3x + 1 so both equations have the same graph

4. #1 times 3 , #2 times 2, then add

9x-6y=30

10x+6y=-30

19x=0.

x=0

put in one equation and solve for y

y=2

5. #1 times 3, then add

9x-15y=0

-9x+15y=-30

0=-30 is a false so there is no solution and the lines are parallel

6. Same here

7. rewrite putting in the milling letters with a zero coefficient

-3x + 4y + 0z = -6

5x +0y -3z = -22

0x +3y +2z = -1

#1 times 5, #2 times 3 and add

-15x +20y +0z = -30

15x +0y -9z = -66

-----------------------------

20y -9z = -96

3y + 2z = -1 mult this by 9 and the one above it by 2, add

40y -18z =-192

27y +18z = -9

------------------

67y = -201

y= - 3 sub this in 3y + 2z = -1,

-9 +2z = -1

2z = 8

z=4 sub this in 5x - 3z =-22

5x - 12 = -22

5x = -10

x= -2

(-2, -3, 4)

check in -3x + 4y = -6

6 + 12 = -6. It works

- Anonymous1 decade ago
well the graphing i can't help with b/c i dont have any graph paper but mostly it would either have 1 solution no solution or infinitely many solutions

the first is infinitely many

the second one has no solution

the third is infinitely many because 0=0

no help on the fourth sorry i havent gotten there yet but please vote best answer

- ?Lv 41 decade ago
Check out this best link:www.intmath.com.When you will check out this website you will forget to ask questions.I have helped you so much plz, plz ,plz give me as best answer.Good Luck

Source(s): As best answer