## Trending News

# physics!! on second law?

A car with a mass of 530 kg is traveling at 43 km/hr. It accelerates to a speed of 122 km/hr in 5.8 seconds. What is the net force acting on the car?

### 3 Answers

- Charles MLv 61 decade agoFavorite Answer
F = ma

a = Δv / Δt

a = (122 kph - 43 kph) / 5.8s

a = 3.78m/s

F = 530kg * 3.78 m/s

F = 2005.3 N

- ukmudgalLv 61 decade ago
________________________________________-

Mass of car = m =530 kg

Initial speed = u =43 km/h=43*5/18=215 / 18 m/s

Final speed = v =122 km /h=122*5 / 18 =610 / 18 m/s

time = t =5.8 s

Acceleration = a =(v - u) / t

Acceleration = a =( 610 /18 -215 /18) / 5.8=21.844 /5.8

Acceleration = a = 3.78 m/s^2

The net force acting on the car =mass*acceleration

The net force acting on the car =530*3.78

The net force acting on the car =2005.27 N

The net force acting on the car is 2005.27 N

_________________________________________________

- Anonymous1 decade ago
force= mass x acceleration

sooo take ur mass and multiply it times your acceleration which you already have