molly asked in Science & MathematicsPhysics · 1 decade ago

physics!! on second law?

A car with a mass of 530 kg is traveling at 43 km/hr. It accelerates to a speed of 122 km/hr in 5.8 seconds. What is the net force acting on the car?

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  • 1 decade ago
    Favorite Answer

    F = ma

    a = Δv / Δt

    a = (122 kph - 43 kph) / 5.8s

    a = 3.78m/s

    F = 530kg * 3.78 m/s

    F = 2005.3 N

  • 1 decade ago

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    Mass of car = m =530 kg

    Initial speed = u =43 km/h=43*5/18=215 / 18 m/s

    Final speed = v =122 km /h=122*5 / 18 =610 / 18 m/s

    time = t =5.8 s

    Acceleration = a =(v - u) / t

    Acceleration = a =( 610 /18 -215 /18) / 5.8=21.844 /5.8

    Acceleration = a = 3.78 m/s^2

    The net force acting on the car =mass*acceleration

    The net force acting on the car =530*3.78

    The net force acting on the car =2005.27 N

    The net force acting on the car is 2005.27 N

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  • Anonymous
    1 decade ago

    force= mass x acceleration

    sooo take ur mass and multiply it times your acceleration which you already have

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