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# need help to find y'?

find y' for y = (1+ (1/x^2))^sqrt(7)

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- 1 decade agoFavorite Answer
Try using the chain rule.

y' = sqrt(7) (1 + x^-2)^ (sqrt(7) - 1) * d/dx[ 1 + x^-2]

y' = sqrt(7) (1 + x^-2)^ (sqrt(7) - 1) * (-2) x^-3

- 1 decade ago
should have asked me this question last year when I was an engineer major sory Im doing premed now

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