Anonymous
Anonymous asked in Science & MathematicsEngineering · 1 decade ago

An unstretched spring wiht a constant of 16N/cm is suspended from the ceiling. A 1.7kg mass is attached to the

spring and let fall. How far does it stretch the spring?

2 Answers

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  • 1 decade ago
    Favorite Answer

    F=-kx

    F=-mg=-(1.7)(9.8)

    (1.7)(9.8)=(16)x

    solve for x...1.04 cm

  • Erika
    Lv 4
    4 years ago

    here the stress utilized via the physique is comparable to the stress utilized via the spring because it fairly is in equilibrium tension simply by physique = mg = kx x is the area displaced and ok is the spring consistent m*10 = 40-one.8*0.05 => m=213 * 10^-3 =.213 kg

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