Anonymous

# What is the number of oxygen atoms?

What is the number of oxygen atoms in 55.0 g of iron(II) hydroxide (Fe(OH)2 (molar mass 89.85 g/mol))?

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First, you want to convert grams of Iron Hydroxide into moles like this: (55.0g/89.85 g mol^-1) which is 0.6121313 moles.

For each mole of Iron Hydroxide there are 2 moles of oxygen, so you multiply 0.6121313 by 2 to get 1.2242626.

Then, you can use Avogadro's number to convert to number of atoms by multiplying 1.2242626 by 6.0221415x10^23 to get your final answer.

Good luck.

Divide the mass by the molar mass of the compound to get moles: 55.0/89.85 = .612 mol. Since the O and the Fe(OH)2 are in a 1:2 ratio, there are 1.22 mol of O. Multiply 1.22 by avogadro's number, and you have atoms of O: 1.22 x (6.022 x 10^23) = 7.37 x 10^23 atoms O.

[(55.0/89.85) x 2] x (6.022 x 10^23)

Divide the mass by the molar mass to get the number of moles. Multiply this by 2 (there are two oxygen atoms in each molecule of iron (II) hydroxide) to get the number of moles of oxygen. Multiply this by Avogadro's number (the number of atoms in a mole) to get the number of Oxygen atoms.

737250973845297718419588.20255941

or

7.37 x 10^23

Is the number I got.

• kately
Lv 4
3 years ago

it incredibly is definitely an undemanding technique to locate the style of oxygen atoms. utilising Avogadro's quantity will supply us the quantity of Methionine molecules. a million mol * (6.02 * 10^23 mol^-a million) = 6.02 * 10^23 molecules of Methionine Methionine is C5H11NO2S, so in a million molecule we've 2 Oxygen atoms. in basic terms multiply the molecules of Methionine by way of two to get your very final answer: (6.02 * 10^23) * 2 = a million.20 * 10^24 atoms of Oxygen

1) Divide 55.0g by 89.85g/mole to get moles of compound.

2) Multiply by 2 because there are 2 moles oxygen atoms in every mole of compound.

3) Multiply by Avogadro's Number to get moles of atoms