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# A straight cylindrical wire having a length of 1.00m & a diameter of 0.40mm is made of a material that obeys..

...Ohm's law with a resistivity of p=8x10^-8 ohms m. If a potential of 8 Volts is maintained across the length of the wire (i.e. between the ends) find (a) the electric field in the wire, (b) the resistance of the wire, (c) the electric current in the wire, (d) the current density in the wire and (e) the drift speed if the number of conduction electrons is 17x10^22 per cubic centimeter. Any help would be greatly appreciated.. :)

### 5 Answers

- Anonymous1 decade agoFavorite Answer
a)

electric field (E) = 8V / 1m

E = 8 V/m

b)

resistance (R)

A(circle) = pi * r²

A = 3.1416 * (0.20/1000)²

A = 1.2566x10^-7

R = pL / A

R = (8x10^-8)(1) / 1.2566x10^-7

R = 0.6366 ohm

c)

electric current (I)

I = V/R

I = 8 / 0.6366

I = 12.566ampere

d)

current density (J)

J= I/A

J = 50.2655 / 1.2566x10^-7

J = 100,000,000 Ampere/m²

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- SparksLv 61 decade ago
(a).

Electric field = voltage / length

Electric field = 8 / 1

Electric field = 8 V/m.

(b).

D = 0∙4mm

→ r = 0∙2 mm

→ r = (0∙2)/1000 m

→ r = 0∙0002 m

A = π r²

A = π(0∙0002)²

A = 0∙000 000 125...

A = 125*10^-9 m²

R = pL / A

R = (8*10^-8)(1) / (125*10^-9)

R = 0∙6636 619 772...Ω

R ≈ 0∙6636 Ω

(c).

I = V/R

I = 8 / 0∙6636 619 772...

I = 12∙566 370 61...

I ≈ 12∙566 A

(d).

D = I / A

D = 12∙566 370 61... / 125*10^-9

D = 100 530 964∙9

D ≈ 100 * 10^6 A/m²

(e).

Drift electrons per unit area will be the issue.

1m² = 100cm * 100cm

1m² = 10,000cm²

But the area of the conductor is: 125*10^-9m²

1m² * 125*10^-9 = 10,000 * 125*10^-9cm²

125*10^-9m² = 1∙570 796 327 * 10^-14cm²

But 17*10^22 electrons pass through a cm² surface area:

No. of electrons = 1∙570 796 327 * 10^-14cm² * 17*10^22

No. of electrons = 267 035 3756

No. of electrons ≈ 2∙67 * 10^9 electrons.

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- MadhukarLv 71 decade ago
(a) Electric field = voltage/length = 8 / 1 = 8 N/C.

(b) Resistance

= ρ( l / A) = 8 x 10^(-8) * (1 / (pi/4)*(0.4 x 10^(-3)^2)

= 0.64 Ω.

(c) Current = voltage / resistance = 8 / 0.64 = 12.5 A.

(d) Current density

= current / cross-sectional area

= 12.5 / (pi/4)*(0.4 x 10^(-3)^2

= 10^8 A/m^2.

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- just meLv 41 decade ago
try reading the book didnt you take notes in class im not helpin you cheat on your test sorry

Source(s): google ohms law calculater i did- Login to reply the answers

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