Anonymous
Anonymous asked in Science & MathematicsMathematics · 1 decade ago

Solve by factoring: 2x2-5x-3=0?

and this one please... Thanks!

x2-9x=0

3 Answers

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  • Anonymous
    1 decade ago
    Best Answer

    2x² - 5x - 3 = 0

    x = [-b ± √(b² - 4ac)]/2a

    x = [-5 ± √(5² - 4(2)(-3))]/2(2)

    x = [-5 ± √(25 + 24)]/4

    x = [-5 ± √(49)]/4

    x = (-5 ± 7)/4

    x1 = 2/4

    x1 = 1/2

    x2 = -12/4

    x2 = -3

    x² - 9x = 0

    x(x-9) = 0

    x = 0 or x - 9 =0

    x = 0 or x = 9

  • 1 decade ago

    (2x+1)(x-3)=0

    x=-1/2 or 3

    x^2-9x=0

    x(x-9)=0

    x=0 or 9

  • Anonymous
    4 years ago

    This Site Might Help You.

    RE:

    Solve by factoring: 2x2-5x-3=0?

    and this one please... Thanks!

    x2-9x=0

    Source(s): solve factoring 2x2 5x 3 0: https://tr.im/k39KB
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