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# Question about factoring trinomials?

Can anyone help me out with factoring this?

5y - 10 - y^3 + 2y^2

I arranged it in descending order and got

-y^3 + 2y^2 + 5y - 10

Now I think im supposed to group the first 2 terms and the last 2 but I get stuck on that step

### 4 Answers

- Astral WalkerLv 71 decade agoFavorite Answer
-y^3 + 2y^2 + 5y - 10

I like to work with polynomials where the first term has coefficient 1

-(y^3 - 2y^2 - 5y + 10)

Now just look to see if there is a grouping you can make to get a common factor. Fortunately you don't have to make any changes to get it.

-[y^2(y - 2) - 5(y - 2)]

-(y^2 - 5)(y - 2)

- Anonymous1 decade ago
you are right,contiue like that:

-y^3 + 2y^2 + 5y - 10= - y^2 (y - 2) +5( y - 2)

(y - 2) ( - y^2 +5)

- rcds23Lv 61 decade ago
Yup, okay well what I did is from there:

Take out a -y^2 and a 5 respectively as such:

-y^2(y-2)+5(y-2). Your goal is to get a common factor in both terms. Now you know the factors are (-y^2+5)(y-2)

- kindrickoLv 71 decade ago
-y^3 + 2y^2 + 5y - 10

-y^2(y - 2) + 5(y - 2)

(-y^2 + 5)(y - 2)

or

-(y^2 - 5)(y - 2)