Anonymous
Anonymous asked in Science & MathematicsMathematics · 1 decade ago

Question about factoring trinomials?

Can anyone help me out with factoring this?

5y - 10 - y^3 + 2y^2

I arranged it in descending order and got

-y^3 + 2y^2 + 5y - 10

Now I think im supposed to group the first 2 terms and the last 2 but I get stuck on that step

4 Answers

Relevance
  • 1 decade ago
    Favorite Answer

    -y^3 + 2y^2 + 5y - 10

    I like to work with polynomials where the first term has coefficient 1

    -(y^3 - 2y^2 - 5y + 10)

    Now just look to see if there is a grouping you can make to get a common factor. Fortunately you don't have to make any changes to get it.

    -[y^2(y - 2) - 5(y - 2)]

    -(y^2 - 5)(y - 2)

  • Anonymous
    1 decade ago

    you are right,contiue like that:

    -y^3 + 2y^2 + 5y - 10= - y^2 (y - 2) +5( y - 2)

    (y - 2) ( - y^2 +5)

  • rcds23
    Lv 6
    1 decade ago

    Yup, okay well what I did is from there:

    Take out a -y^2 and a 5 respectively as such:

    -y^2(y-2)+5(y-2). Your goal is to get a common factor in both terms. Now you know the factors are (-y^2+5)(y-2)

  • 1 decade ago

    -y^3 + 2y^2 + 5y - 10

    -y^2(y - 2) + 5(y - 2)

    (-y^2 + 5)(y - 2)

    or

    -(y^2 - 5)(y - 2)

Still have questions? Get your answers by asking now.