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# Standard and General Form of the Circle's Equation?

Write the standard form of the equation and the general form of the equation of each circle of radius r and center (h, k).

(1) r = 3; (h, k) = (0, 0 )

(2) r = 5; (h, k) = (-5, 2)

### 5 Answers

- teddy boyLv 61 decade agoFavorite Answer
(1) r = 3; (h, k) = (0, 0 )

General Form:

x^2 + y^2 - 2hx - 2ky + h^2 + k^2 - r^2 = 0

x^2 + y^2 + 2(0)x - 2(0)y + 0^2 + 0^2 - 3^2 = 0

x^2 + y^2 - 3^2 = 0

x^2 + y^2 - 9 = 0 ANS.

Standard Form:

(x - h)^2 + (y - k)^2 = r^2

(x - 0)^2 + (y - 0)^2 = 3^2

x^2 + y^2 = 9 ANS.

2) r = 5; (h, k) = (-5, 2)

General Form:

x^2 + y^2 - 2hx - 2ky + h^2 + k^2 - r^2 = 0

x^2 + y^2 - 2(-5)x - 2(2)y + (-5)^2 + 2^2 - 5^2 = 0

x^2 + y^2 + 10x - 4y + 25 + 4 - 25 = 0

x^2 + y^2 + 10x - 4y + 4 = 0 ANS

Standard Form:

(x - h)^2 + (y - k)^2 = r^2

(x - -5)^2 + (y - 2)^2 = 5^2

(x + 5)^2 + (y - 2)^2 = 25 ANS

teddy boy

- Anonymous6 years ago
RE:

Standard and General Form of the Circle's Equation?

Write the standard form of the equation and the general form of the equation of each circle of radius r and center (h, k).

(1) r = 3; (h, k) = (0, 0 )

(2) r = 5; (h, k) = (-5, 2)

Source(s): standard general form circle 39 equation: https://trimurl.im/j56/standard-and-general-form-o... - cidyahLv 71 decade ago
The standard form is (x-h)^2+(y-k)^2=r^2, (h,k) is the center and r, the radius.

1) (x-0)^2+(y-0)^2=3^2

=x^2+y^2=9

2)(x-(-5))^2+(y-2)^2=5^2

(x+5)^2+(y-2)^2=25

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- Anonymous1 decade ago
With centre (0,0) it is x^2 + y^2 = r^2

(1) x^2 + y^2 = 9