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# 2 math questions?

What temperature, in degrees Fahrenheit, is equivalent to a temperature of 10° Celsius?

and

Lines AB and CD intersect at point E. If m<AEC=5x-20, and m<BED=x+50, find m<CEB.

### 1 Answer

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- KiaLv 61 decade agoFavorite Answer
Fahrenheit = (Celsius * 9/5) + 32

Fahrenheit = (10 * 9/5) + 32

Fahrenheit = 18 + 32

Fahrenheit = 50

m<AEC = m<BED

5x - 20 = x + 50

5x - x = 50 + 20

4x = 70

x = 70 / 4

x = 17.5

m<AEC = 5x - 20

m<AEC = 5(17.5) - 20

m<AEC = 87.5 - 20

m<AEC = 67.5

m<CEB = 180 - m<AEC

m<CEB = 180 - 67.5

m<CEB = 112.5

I hope this helped

Kia

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