Find the primeter of a rectangle L= x/2x-5 and the w= 8/2x-5?

Answer 1

P = 2L + 2W

= 2(x/(2x-5)) + 2(8/(2x-5))

= (2x + 16)/(2x -5)

Do you have any other information? If not, then this is the final answer.

Answer 2

P = 2L + 2w
= 2( x/2x-5) + 2(8/2x-5)
= 2 x + 16/ 2x - 5

Answer 3

Assuming you meant L= (x/2x)-5 and w= (8/2x)-5 as you have expressed it...

P = 2L + 2W = [(2x/2x)-10 ] + [(16/2x)-10]
= [-9] + [(8/x) - 10]
=(8/x) - 19

Answer 4

Unless there is no more information given the answer is as follows...

Perimeter = 2L + 2W
P=(2x)/(2x-5) + 16/(2x-5)
P=(2x+16)/(2x-5)

If there is more information given, I might be able to give you a numerical answer.

Answer 5

and x cannot be </= 2.5 because then perimeter would be a negative number or (at 2.5) it would be undefined.
so x has to be > 2.5
now as x approaches 2.5 from the right, the perimeter increases without bound.
as x increases from 2.5 to positive infinity, the perimeter decreases and approaches 0