# How many grams of carbon dioxide are contained in 550 mL of this gas at STP?

How many grams of carbon dioxide are contained in 550 mL of this gas at STP?

The choices are -

a 0.0245 g

b 0.0280 g

c 1080 g

d 0.560 g

e 1.1 g

### 4 Answers

Relevance

- papastolteLv 61 decade agoFavorite Answer
e. 1.1g

Find moles from 1mol =22.4L

mol CO2 = 0.550 L / 22.4 L/mol = 0.025 mol CO2

Find grams by multiplying by Molar Mass of CO2, 44.0g/mol

g = 0.025 mol x 44.0g/mol = 1.10g CO2

Note: Use a calculator to check these numbers. I did them in my head.

- Anonymous1 decade ago
use the formula:

PV=nRT

P=101.3kPa

V=0.55L

n=? (what we need to find)

R=constant (8.315)

T=273K

rearrange the formula so n equals

n=PV/RT

n=101.3x0.55/8.315x273

n=2.45x10^-2 moles of CO2

Using n=m/M, rearrange to get mass

m=nM

M(CO2)=12.01+16x2

=44.01g/mol

m=(2.45x10^-2)x44.01

m=1.08grams which is closer to 1.10grams (e)

Therefore, the answer is e.

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