## Trending News

Anonymous

# quick math question; exponenets?

(Pf) x (Vf)^x = (Pi) x (Vi)^x

I need to solve for Vi

I came up with

Vi = ((Pf) + ( Vf^x) - (Pi)) / (e^x)

can anyone confirm?

### 2 Answers

Relevance

- 1 decade agoFavorite Answer
Take the log of both sides of the equation, separate out (Vi), then exponentiate:

(Pf) (Vf)^x = (Pi) (Vi)^x

log(Pf) + xlog(Vf) = log(Pi) + xlog(Vi)

xlog(Vi) = log(Pf) + xlog(Vf) - log(Pi)

log(Vi) = (log(Pf) + xlog(Vf) - log(Pi))/x

(Vi) = exp[(log(Pf) + xlog(Vf) - log(Pi))/x]

(Vi) = [(Pf) + (Vf)^x - (Pi)]/(e^x)

Yep.

- Login to reply the answers

- 1 decade ago
p cancels as does v^x:

f^(x+1)=i^(x+1) so f=i....

its an identity so how cn u singl out Vi???

- Login to reply the answers

Still have questions? Get your answers by asking now.