Ca(OH)2(s) + CO2(g) CaCO3(s) + H2O(g)?

Ca(OH)2(s) + CO2(g) CaCO3(s) + H2O(g)

(a) Calculate the standard enthalpy change for this reaction __kJ

(b) What quantity of heat is evolved or absorbed if 1.30 kg of Ca(OH)2 reacts with a stoichiometric amount of CO2? ___kJ

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  • 1 decade ago
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    Ca(OH)2(s) + CO2(g) CaCO3(s) + H2O(g)

    Ca(OH)2(s) = -986.2 kj

    CO2(g) = -393.5kj

    CaCO3(s)= -1207 kj

    H2O(g)= -241.8 kj

    delta H = prod - reactants

    = (-1207 kj & -241.8 kj) - (-986.2 & -393.5)

    = -1448.8 -( -1379.7)

    FIRST ANSWER= -69.1 kJ

    -----------------------

    -69.1kj per mole Ca(OH)2 divided by 74 grams per mole=

    -0.934 kJ per gram

    times 1300grams of Ca(OH)2 +

    SECOND ANSWER: delta H of -1214kJ (released)

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