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# Maths--algebra

how to set up the equation?

Peter has $9 more than Paul,and Philip's is 1/3 of Peter's.How much money does each of them have if they have a total of $61

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### 2 Answers

- 華里之Lv 41 decade agoFavorite Answer
Let x be the money that Peter have, then Paul has $x-9 and Philip has $1/3x

x+1/3x+(x-9) = 61

x+1/3x+x-9 = 61

x+1/3x+x = 61+9

2x+1/3x = 70

6x/3+1x/3 = 70 (通分母)

7x/3 = 70

7x = 70 X 3

7x = 210

x= 210/7

x= 30

Checking:

left hand side: 30+(30-9)+(1/3 X 30)=61

right hand side: 61

left hand side = right hand side

So, Peter has $30, Paul has 30-9=$21 and Philip has 30 X 1/3 = $10

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Source(s): ME - 1 decade ago
answer: let X be the money that Peter have, then Paul have X-9, Philip have X/3

X + X-9 + X/3 = 61

7X/3 -9 = 61

7X = 210

X = 30

So Peter have $30, Paul has $21 and Philip have $10