AB asked in 科學及數學數學 · 1 decade ago

Maths--algebra

how to set up the equation?

Peter has $9 more than Paul,and Philip's is 1/3 of Peter's.How much money does each of them have if they have a total of $61

Update:

俾個詳細D ge步驟得唔得

2 Answers

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  • 1 decade ago
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    Let x be the money that Peter have, then Paul has $x-9 and Philip has $1/3x

    x+1/3x+(x-9) = 61

    x+1/3x+x-9 = 61

    x+1/3x+x = 61+9  

    2x+1/3x = 70

    6x/3+1x/3 = 70 (通分母)

    7x/3 = 70

    7x = 70 X 3

    7x = 210

    x= 210/7

    x= 30

    Checking:

    left hand side: 30+(30-9)+(1/3 X 30)=61

    right hand side: 61

    left hand side = right hand side

    So, Peter has $30, Paul has 30-9=$21 and Philip has 30 X 1/3 = $10

    係詳細D ge步驟!!

    希望幫到你!

    Source(s): ME
  • 1 decade ago

    answer: let X be the money that Peter have, then Paul have X-9, Philip have X/3

    X + X-9 + X/3 = 61

    7X/3 -9 = 61

    7X = 210

    X = 30

    So Peter have $30, Paul has $21 and Philip have $10

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