physics Speed and Velocity

1 . The prower of ferrari 430 is huge . If it accelerates from rest along a straight lne,its maximum acceleration is about 6.5 m s^ -2 . What is the shortest time it takes to accelerate from rest to 100 km h^-1 ?

(Hints:Convert the final velocity from km h^-1 into m s^-1)

2 Answers

Rating
  • 小儒
    Lv 5
    1 decade ago
    Favorite Answer

    This is a standard mechanics question on consolidation

    We use the following equation:

    v = u + at

    1.

    Now, 100 kmh^-1 = 100*1000/3600 = 250/9 ms^-1

    So, 250/9 = 0 + (6.5)(t)

    This follows t = 500/117 = 4.27 ms^-1

    Hope the above information helps you =)

    By 小儒

  • 1 decade ago

    acceleration = (final speed - initial speed ) / time

    let t be the time needed

    100 km h^-1 = 27.78 m s^-1

    so,

    6.5=(27.78 - 0) / t

    t=4.274 second

    the shortest time it takes is about 5 seconds.

    hope it can help you =)

    Source(s): myself
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