How to evaluate the trigonometric function using its period as an aid. sin5pi?
- 1 decade agoFavorite Answer
Since the period of sine function is 2 pi, subtract 2 pi from 5 pi twice and you'll end up with sin pi. You can now find the answer by evaluating sin pi. The answer then is 0.
- HkLv 41 decade ago
The period of sin is 2pi
So, sine 5pi = sin 3pi = sin pi
si pi = sin (180degress ) = 0