Anonymous
Anonymous asked in Science & MathematicsMathematics · 1 decade ago

How to evaluate the trigonometric function using its period as an aid. sin5pi?

2 Answers

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  • 1 decade ago
    Favorite Answer

    Since the period of sine function is 2 pi, subtract 2 pi from 5 pi twice and you'll end up with sin pi. You can now find the answer by evaluating sin pi. The answer then is 0.

  • Hk
    Lv 4
    1 decade ago

    The period of sin is 2pi

    So, sine 5pi = sin 3pi = sin pi

    si pi = sin (180degress ) = 0

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