F.3 maths X1
1. A barrel contains 10 L wine, 6% of which is alcohol. If 2 L of wine is poured out and 2 L of water is added, what is the percentage of alcohol in the wine now?
*please show the process, thanks.
- Audrey HepburnLv 71 decade agoFavorite Answer
After 2 L wine is poured out,
Volume of wine remained
= 10 - 2
= 8 L
Volume of alcohol in 8 L of wine
= 8 X 6%
= 0.48 L
Also, 2 L of water is added.
So, total volume of the mixture
= 8 + 2
= 10 L
Therefore, percentage of alcohol in the wine now
= 0.48 / 10 X 100%
= 4.8 %Source(s): Myself~~~
- 1 decade ago
1) we should find out the volume of alcohol in 2L of wine
the volume of alcohol in 2L = 10L x 6% ÷ 10/2 = 0.12L
the original volume of alcohol in the wine
= 10L x 6% = 0.6L
The percentage of alcohol in the wine
= [( 0.6L - 0.12L) ÷10L] X100%
so the percentage of alcohol in the wine is 4.8%.