# F.3 maths X1

1. A barrel contains 10 L wine, 6% of which is alcohol. If 2 L of wine is poured out and 2 L of water is added, what is the percentage of alcohol in the wine now?

*please show the process, thanks.

### 2 Answers

- Audrey HepburnLv 71 decade agoFavorite Answer
After 2 L wine is poured out,

Volume of wine remained

= 10 - 2

= 8 L

Volume of alcohol in 8 L of wine

= 8 X 6%

= 0.48 L

Also, 2 L of water is added.

So, total volume of the mixture

= 8 + 2

= 10 L

Therefore, percentage of alcohol in the wine now

= 0.48 / 10 X 100%

= 4.8 %

Source(s): Myself~~~- Login to reply the answers

- 1 decade ago
1) we should find out the volume of alcohol in 2L of wine

the volume of alcohol in 2L = 10L x 6% ÷ 10/2 = 0.12L

the original volume of alcohol in the wine

= 10L x 6% = 0.6L

The percentage of alcohol in the wine

= [( 0.6L - 0.12L) ÷10L] X100%

=4.8%

so the percentage of alcohol in the wine is 4.8%.

這是我自己計的，希望可以幫到你！！

Source(s): myself- Login to reply the answers