Anonymous
Anonymous asked in Science & MathematicsPhysics · 1 decade ago

a body in uniform acceleration covers 75m in6th sec 115m in 11th sec . Find displacement in 16th sec?

note: it is given 6th second not 6 second. moreover give full solution not only answer

3 Answers

Relevance
  • 1 decade ago
    Favorite Answer

    from the 6th sec to 11th sec is 5 seconds.

    Find acceleration

    Xf = .5at^2

    115 = .5(a)(5)^2

    230 = 25a

    a = 9.2 m/s^2

    assume the question ask for the displacement from 6th sec to 16th sec

    so from 6th sec to 16th sec is 10 seconds

    Xf = .5at^2

    Xf = .5(9.2)(10)^2

    Xf = 460m

    just in case the question ask for the displacement from 11th sec to 16th sec.

    First you got to find the speed at which the body reaches at the end of 115m

    Vf^2 = 2ad + Vi^2

    Vf^2 = 2(9.2)(115) + 0^2

    Vf^2 = 46 m/s

    Xf = .5at^2 + Vt + Xi

    Xf = .5(9.2)(5)^2 + 56(5)

    Xf = 345m

  • 1 decade ago

    Distance traveled in the nth second is

    S = U + [n-1/2] a

    75 = U + 5.5 a. and =========1

    115 = U + 10.5 a ==============2

    2 -1 gives

    40 = 5a

    a = 8 m/s^2

    From 1

    U = 31 m/s

    Displacement in 16th sec

    = 31 + 15.5 * 8 = 155m.

  • 4 years ago

    i think of that's going to grow to be one because of the fact i do no longer think of LSU will forget approximately the cheap shot on Dorsey. That became probable the dirtiest play I rather have ever seen in 20+ years of staring at soccer. i think of FLA- Tennessee is the 2nd terrific opposition.

Still have questions? Get your answers by asking now.