# Algebra problem, solve for B?

B/2 = -7 + B , solve for B

Thanks!

Relevance

b/2 = -7 + b

==> b = (-7 + b) * 2

==> b = -14 + 2b

==> 14 = b

B/2=-7+B

or 2B/2=2(-7+B)

or B=-14+2B

or B-2B=-14+2B-2B

or -B=-14

Or B=14 ans

B/2=-7+B

rearrange to get

B/2 - B = -7

Change signs to get:

B - B/2 = 7

Factorise lhs

B(1-1/2) = 7

B(1/2) = 7

Multiply both sides by 2/1 to solve for

B=14

• Anonymous

B/2 = -7 + B

B = 2(-7 + B) [explanation: both sides * 2]

B = -14 + 2B

-B = -14 [explanation: - 2B on both sides]

B = 14 [explanation: *-1 on both sides]

B/2 = -7 + B multiply both sides by 2

(*2)B/2 = 2(-7+B) simplify

B = -14 + 2B subtract 2B from both sides

B (-2B) = -14 + 2B (-2B) simplify

-B = -14 divide by a negative to isolate your variable

-B/- = -14/- simplify

B = 14

--------------------------------------------------------------------------

TO CHECK:

Put your value for B which is 14 in the equation where B is located

14/2 = -7+14

7 = 7

and the answers are the same so it is correct

Source(s): my head - I'm a teacher
• Anonymous

B/2 = -7 + B

B = -14 + 2B (multiplied both sides by 2)

B = -14 (subtract a B from both sides)

Source(s): Easy math
• ?
Lv 6

Hey there!

B/2=-7+B --> Write the problem.

B=-14+2B --> Multiply 2 on both sides of the equation.

-B=-14 --> Subtract 2B on both sides of the equation.

B=14 Divide both sides of the equation by -1.

Hope it helps!

Multiply across by 2 to get B= -14 +2B

Subtract 2B from both sides to get -B= -14

Divide by -1 to get B=14

So B = 14

Source(s): My algebra class

Multiply both side by 2

B = -14 + 2B

B = 14/2 = 7

B/2=-7+B

2 * (B/2)=2 * -7+2 * B

B= -14+2B

-2B -2B

-B=-14

-1*(-B)=-1*(-14)

B=14

hope that helps!