Please someone help with this math probability question?

The probability that a certain brand of calculator is defective is known to be 0.2. Determine the probability that if 5 such calculators are examined none are found to be defective.

2 Answers

Relevance
  • 1 decade ago
    Favorite Answer

    P(not defective) = 1 - 0.2 = 0.8

    P(5 aren't defective) = 0.8 * 0.8 * 0.8 * 0.8 * 0.8

    = (0.8)^5

    = 0.32768

  • swd
    Lv 6
    1 decade ago

    0.8^5

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