Anonymous
Anonymous asked in Science & MathematicsChemistry · 1 decade ago

Chemistry question: How does rydberg's constant fit into a straight line equation?

This refers to the equation 1/lambda = Rydberg's constant * (1/n initial^2) +(1/n final^2) where lambda equals a certain wavelength and n initial equals a number greater than or equal to 2. How can you possibly plot points for 1/lambda vs 1/n initial (since this equation is that of a straight line)?

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  • 1 decade ago
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    y = mx + b (the equation of a straight line)

    y = 1/lambda

    m = Rydberg's constant

    x = (1/n initial^2)

    b = (1/n final^2)

    now she the light? if you know lambda and n initial then you just plug in (i.e. if lambda = 100, then the y coordinate is 1/100; if n initial = 2, then the x coordinate = (1/2^2)). the slope will be Rydberg's constant and where the line crosses the y-axis will be (1/n final^2) (or 'b' in the traditional line equation)

    BF

    4th yr Chem Major

    U of O (Canada)

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