Instantaneous velocity problem?

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  • Anonymous
    1 decade ago
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    You need to estimate the gradient of a graph at the point corresponding to date 1980.

    The rate of growth form 1960 to 1980 was 278/20 = 13.9 people per year. From 1980 to 2000 it was 384/20 = 19.2 people per year.

    Unless you are expected to plot a graph, or use a more sophisticated method, I would suggest an average of those two rates at 16.55 people per year is good enough as an estimate.

  • 1 decade ago

    The instantaneous Velocity would be the velocity or slope of the graph at that one point year 1980.

    It would be Population / Year or 868 / 100 years--I said 100 years because its 100 years away from the starting date, assuming that 1880 was year 0.

    I just read the other posts, you don't want to average the slopes from above and below the point 1980 because it will yield a # that is similar but not exact. As the intersection between those two points grows smaller and becomes tangent with the point at 1980, it will be the same as the population / the year.

  • 1 decade ago

    (1252-590)/40=16.55 people per year

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