Anonymous
Anonymous asked in Science & MathematicsMathematics · 1 decade ago

crucial values( f '' )?

what are the crucial values(f '') for

f(x)= 8x^(1/3) + x^(4/3)

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  • 1 decade ago
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    f'(x) = (1/3)*8*x^(-2/3) + (4/3)*x^(1/3)

    f''(x) = (-2/9)*8*x^(-5/3) + (4/9)*x^(-2/3)

    To find the critical values of f'', you need to set it equal to 0.

    f''=0=(-2/9)*8*x^(-5/3) + (4/9)*x^(-2/3)

    (2/9)*8*x^(-5/3) = (4/9)*x^(-2/3)

    (16/9)x^(-5/3) = (4/9)x^(-2/3)

    16x^(-5/3) = 4x^(-2/3)

    4 = x^(-2/3 + 5/3)

    4 = x

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