Coefficient of Thermal Expansion of Gasoline?

Do you believe the Coefficient of Thermal Expansion of Gasoline is high enough to make it worth it to only buy gas at night when it is cold?

Prove it.

6 Answers

  • ?
    Lv 5
    1 decade ago
    Best Answer

    Gasoline - 0.000950 / (C or K)

    We'll say a 15 degree (C or K) temperature change.

    ΔV = V0βΔT

    ΔV = (1gallon)(0.000950)(15)

    ΔV = 0.01425gallons

    So at night, you get 1 gallon and the next day it expands to 1.01425 gallons.

    It breaks down to this:

    During the day you pay $40. At night you would get that same amount of gas for $39.44.

    Source(s): . . You save ~1% for every 10C drop in temperature. . .
    • El2 years agoReport

      Since gasoline is stored in underground tanks, the temperature varies very little and there should be no if any difference between day and night pumped gasoline.

  • Erika
    Lv 4
    3 years ago

    Volume Coefficient Of Expansion

  • 1 decade ago

    Although it 1 gallon of hot gasoline contains less substance,

    it does not mean that that when you buy 1 gallon of hot

    gasoline you buy less. The trick is that while you assume

    that the pump pours the exact volume as it displays,

    in relaity it displays what it _thinks the volume is.

    The parts of measuring mechanism undergo thermal

    expansion too, and it affects measurement errors.

    For example if you imagne that there is a homonuclus

    inside the pump, who pours you 1000 teaspoonful of gasoline

    whenever you by one gallon, the actual result depend

    on the volume of the teaspoon, which expands with

    temperature too.

  • 4 years ago

    Using a graph, the coldest part of the day is not at night but just before the sun rises

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  • Anonymous
    3 years ago

    Every time I post a question, even if it is the simplest one, they cannot provide me a good informed answer here. what happened to people who actually take the time to answer?

  • Tracy
    Lv 4
    4 years ago

    For the best answers, search on this site

    ΔV = V0*β*ΔT = 1L*9.50x10^-4*20 = 0.019L

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