How many liters of CO2 are produced when 400. g CaCO3 reacts with HCl?
How many liters of CO2 are produced when 400. g CaCO3 reacts with HCl in the following reaction at STP? CaCO3 + 2 HCl ® CaCl2 + CO2 + H2O
- Anonymous1 decade agoFavorite Answer
The term you need is this.
One mole of any molecule (g) is 22.4 moles per liter.
- flandargoLv 51 decade ago
1. Calculate the molar mass of calcium carbonate. (1x40 + 1x12 +3x16 = 100 g).
2. Convert the given mass to moles (400 g / 100 g per mole = 4 moles)
3. Deduce ratio of moles of CaCO3 to moles of CO2 IN THE BALANCED EQUATION (1:1, in this case).
4. So, if you actually have 4 moles of CaCO3, you will get 4 moles of CO2.
5. Since 1 mole of ANY gas at STP occupies 22.4 dm^3 (or L), then 4 moles will occupy 4 time 22.4 L
Apply the same principles in all future questions like this, please. It took me a long time to write this.