Anonymous
Anonymous asked in Science & MathematicsMathematics · 1 decade ago

Determine if the line 2x-y=2 is a secant, tangent or neither of the circle?

The equation of circle is (x-6)^2 + (y+2)^2=36.

Determine if the line 2x-y=2 is a secant, tangent or neither of the circle.

3 Answers

Relevance
  • Anonymous
    1 decade ago
    Favorite Answer

    ♠ thus

    ♪ 2x-2=y and

    ♫ (x-6)^2 +(y+2)^2=36;

    stick y from (♪) into (♫); then

    ♣ (x-6)^2 + (2x-2+2)^2=36; or;

    (x^2 –12x +36) + 4x^2 =36; or;

    5x^2 –12x=0; or; (5x –12)*x=0, hence x1=0, x2=2.4;

    ♦thus (see ♪) y1=2*x1-2=-2, y2=2.8;

    ♥ 2 points (0,-2) and (2.4,2.8);

    conclusion: line 2x-y=2 is a secant;

  • 1 decade ago

    If you graph out both equations, you'll see its a secant. (The coordinates of the circle is C(6,-2) and a radius of 6. So, then you graph the line and you get a y intercept of -2. (you end up getting y=2x-2). There's also a algebraic way you can do it but I don't remember how. Sorry.

  • 1 decade ago

    it is a secant, the line intersects the circle at exactly 2 points

Still have questions? Get your answers by asking now.