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# Determine if the line 2x-y=2 is a secant, tangent or neither of the circle?

The equation of circle is (x-6)^2 + (y+2)^2=36.

Determine if the line 2x-y=2 is a secant, tangent or neither of the circle.

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- Anonymous1 decade agoFavorite Answer
♠ thus

♪ 2x-2=y and

♫ (x-6)^2 +(y+2)^2=36;

stick y from (♪) into (♫); then

♣ (x-6)^2 + (2x-2+2)^2=36; or;

(x^2 –12x +36) + 4x^2 =36; or;

5x^2 –12x=0; or; (5x –12)*x=0, hence x1=0, x2=2.4;

♦thus (see ♪) y1=2*x1-2=-2, y2=2.8;

♥ 2 points (0,-2) and (2.4,2.8);

conclusion: line 2x-y=2 is a secant;

- 1 decade ago
If you graph out both equations, you'll see its a secant. (The coordinates of the circle is C(6,-2) and a radius of 6. So, then you graph the line and you get a y intercept of -2. (you end up getting y=2x-2). There's also a algebraic way you can do it but I don't remember how. Sorry.

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