calculus helppp arc length?
Set up, but do not evaluate, an intergral that represents the length of the curve:
1) y = cosx, [0, 2pi]
Graph the curve and find its exact length:
2) x = 1 + 3t^2, y = 4 + 2t^3, [0, 1]
3) x = y^(3/2), [0, 1]
Please show all work/steps so I know how you got the answer..Thanks! :)
- Anonymous1 decade agoFavorite Answer
The length along a curve is found by integrating between the appropriate limits sqrt(1 + (dy/dx)^2).