Anonymous
Anonymous asked in Science & MathematicsMathematics · 1 decade ago

math heelp please?

AB (arrow on top of it) intersect CD (arrow on top of it) at E, m<AEC=3x, and m<AED=5x-60

a.findx

b.show that AB (arrow on top of it) is perpindicular to CD (arrow on top of it)

i mean an arrow like left and right

2 Answers

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  • 1 decade ago
    Favorite Answer

    AEC+AED=180 (since, it is a straight line)

    3x+5x-60=180

    8x=240

    x=30

    AEC=3x=90

    AED=5x-60=90

    AB is perpendicular to CD

  • 1 decade ago

    The two angles (AEC and AED) are supplementary angles - they share a common ray and are adjacent to each other on the same line (CED). Supplementary angles have a sum of 180 degrees. SO angles AEC and AED add up to 180.

    3x + 5x - 60 = 180

    8x - 60 = 180

    8x = 240

    x = 30

    m<AEC = 3x = 3(30) = 90

    m<AED = 5x - 60 = 5(30) - 60 = 150 - 60 = 90

    The lines are perpendicular to each other because perpendicular lines form right (90 degrees) angles and they do!

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