math heelp please?
AB (arrow on top of it) intersect CD (arrow on top of it) at E, m<AEC=3x, and m<AED=5x-60
b.show that AB (arrow on top of it) is perpindicular to CD (arrow on top of it)
i mean an arrow like left and right
- 1 decade agoFavorite Answer
AEC+AED=180 (since, it is a straight line)
AB is perpendicular to CD
- 1 decade ago
The two angles (AEC and AED) are supplementary angles - they share a common ray and are adjacent to each other on the same line (CED). Supplementary angles have a sum of 180 degrees. SO angles AEC and AED add up to 180.
3x + 5x - 60 = 180
8x - 60 = 180
8x = 240
x = 30
m<AEC = 3x = 3(30) = 90
m<AED = 5x - 60 = 5(30) - 60 = 150 - 60 = 90
The lines are perpendicular to each other because perpendicular lines form right (90 degrees) angles and they do!