Yahoo Answers is shutting down on May 4th, 2021 (Eastern Time) and beginning April 20th, 2021 (Eastern Time) the Yahoo Answers website will be in read-only mode. There will be no changes to other Yahoo properties or services, or your Yahoo account. You can find more information about the Yahoo Answers shutdown and how to download your data on this help page.

I have one AP Physics Free-Response Question.Can you jst give me answer or give me hint throug ths question.?

While Exploring a sunken ocean liner, the principal resercher found the absolute pressure on the robot observation submarine at the level of the ship to be about 413 atmoshpere. The density of seawater is 1025 kg/m^3.

(a)How do i find gauge pressure on the sunken ocean liner

(b)Calculate the depth of the sunken ocean liner.

(c)Calculate the magnitude F of the force due to water on a viewing part of the submarine at the this depth if the viewing port has surface area of 0.0100m^2.

Suppose that ocan liner came to rest at the surface of the ocean before at started to sink .due to resistance of sea water,the sinking ocean liner then reached a terminal velocity 10.0m/s after falling 30.0 second.

(d)Find the acceleration of ocean liner during this period of time.

(e)Assume that Acceleration was constant, find the distance below the surface at which ocean liner riched the terminal velocity.

(f)find t it took the ocean liner to sink from surface to the bottom of ocean

1 Answer

Relevance
  • 1 decade ago
    Favorite Answer

    (a) you need to know the diff between gauge pressure and absolute pressure (probably 1 atm at sea level, assuming the ocean liner is in the ocean and not in the Dead Sea).

    (b) calculate the force of gravity on the gauge from the column of seawater - be careful in the units conversion from kg/m3 to pascals, psi or atm. Or use a standard equation.

    (c) water pressure is 413 atm - convert that to psi or some force per area unit, then multiply it times the area of the viewport.

    (d) initial sinking velocity Vo= 0 m/s, then accelerated to 10 m/s in 30 secs. Assuming accel is linear, accel = (V'-Vo)/(T'-To) or delta-V over delta-T.

    (e) use x =(at^2)/2 for distance under accel

    (f) obvious from (B) and (E)

    Go in peace.

Still have questions? Get your answers by asking now.