V asked in Science & MathematicsChemistry · 1 decade ago

Calculate the pH of 0.10 M KNO2 (aq). Ka for HNO2 is 4.3 x 10 ^ -4?

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  • Anonymous
    1 decade ago
    Favorite Answer

    KNO2 is a strong electrolyte

    KNO2 >> K+ + NO2-

    NO2- + H2O <> HNO2 + OH-

    initial concentration

    0.10 . . . . . . . . . . .0 . . . . .0

    at equilibrium

    0.10-x . . . . . . . . . . . x . . . . . x

    For this equilibrium

    K = Kw / Kb = 10^-14 / 4.3 10^-4 = (x)(x)/ 0.1-x =2.32 10^-11

    x = 1.52 10^-6

    pOH =5.82

    pH=8.18

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  • 5 years ago

    This Site Might Help You.

    RE:

    Calculate the pH of 0.10 M KNO2 (aq). Ka for HNO2 is 4.3 x 10 ^ -4?

    Source(s): calculate ph 0 10 kno2 aq ka hno2 4 3 10 4: https://biturl.im/k02Gj
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  • Sharon
    Lv 4
    4 years ago

    For the best answers, search on this site https://shorturl.im/EClAJ

    4.0 x 10^-4 = x^2 / 1.04-x solve for x by quadratic formula x = [H+] pH = - log x

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