工程科學應力應變題 Ex1~Ex2 ?

Acceleration due to gravity = 10 ms-2;

Calculation steps should be clearly shown;

Answers correct to two decimal places.

1. Determine the resultant and its position of the system of forces 200N15度角, 150N100度角, 120N-120度角 and 300N-50度角.

2. ABCD is a light inextensible string passing round a smooth pulley C and a force F (N) applied at B in a direction perpendicular to the string maintains equilibrium. Determine the magnitude of F and the angle BCD.

1 Answer

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  • 1 decade ago
    Favorite Answer

    1) resolve the forces into x, y direction

    x- direction

    200sin15 + 300sin50 + 150cos10 + 120cos30

    =533N

    y- direction

    200cos15 + 300cos50 - 150sin10 - 120sin30

    =300N

    resultant

    (533^2+300^2)^0.5

    =612N

    bearing

    90-tan^-1(300/533)

    =60.6 deg

    2) sorry,

    there seems to be no any weight, how comes a force is needed to balance?

    Source(s): myself
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