Professional help please.?
Is this a thermodynamically possible reaction at T= 1173 K ?
2(Ca^2+) + TiO2 ---> (Ti^4+) + 2CaO
The ions and CaO are dissolved in the same liquid, but very dilluted.TiO2 is in solid state. DG needs to be calculated.
I don't give you my DG's for the participants, because may not be accurate. You can calculate ion's DG's useing their standard potentials. Thank you very much. Any answer will be very important for me. The closest one will be the best one.
Take your time, please
- Doctor QLv 61 decade agoFavorite Answer
The reaction is definately possible, as Calcium melts at 839 celsius (1112 Kelvin) and would therefore be molten.
I'm not sure how to work out your question though. This process is called the FCC Cambridge process, which you can read about here....
Sorry I couldn't help you more...