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# Math.........................?

Bea raised some cows and some turkeys. She raised a total of 28 cows and turkeys. There were 96 legs in all. How many cows and turkeys did Bea raise?

### 11 Answers

- Anonymous1 decade agoFavorite Answer
You want to set up two equations. Let x be the number of cows, and let y be the number of turkeys. Since there are a total of 28, you know that:

x + y = 28

You also know that cows have four legs, and turkeys have two legs. The number of legs that all the cows have is 4x. The number of legs that all the turkeys have is 2y. So you know that:

4x + 2y = 96

Now solve by substitution or elimination. I personally like elimination, so I multiply the first equation by 2 and subtract it from the other:

x + y = 28

2x + 2y = 56

(4x + 2y) - (2x + 2y) = 96 - 56

2x = 40

x = 20

So there are twenty cows. Since there are twenty-eight total, there must be eight turkeys.

- jaybeeLv 41 decade ago
let c=number of cows

let t=number of turkeys

the total number of both is 28, so

c+t = 28

this can be rearranged:

t= 28 - c

i think we can safely assume that each cow has 4 legs and each turkey has two, so:

4c+ 2t = 96 now let's substitute 28-c for t (from above):

4c +2(28-c)=96

4c +56 -2c = 96

2c = 40

c = 20

so t=28-20 = 8

checking:

4(20) + 2(8) = 80 + 16 = 96 checks

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- John SLv 61 decade ago
Let x = the number of cows

4x + 2(28-x) =96

4x + 56 -2x = 96

x = 20 (cows)

(28 - x) = 8 (turkeys)

- 1 decade ago
divide 4legs for the cow into 96legs total and you get 24 even,

the difference between 24 and 28 is 4, and turkeys have 2 legs each, so divide 2 into 4 and you get 2.

So the answer is 24 cows and 2 turkeys

- Anonymous1 decade ago
20 cows and 8 turkeys

- Michael Dino CLv 41 decade ago
x = number of turkeys

y = number of cows

x + y = 28

2x + 4y = 96

solve for x and y

x = 28 - y

2(28 - y) + 4y = 96

56 + 2y = 96

2y = 40

y = 20

x = 8

Test it out.

8 turkeys means 16 legs

20 cows means 80 legs

total is 96

- 1 decade ago
x = amount of cows

y = amount of turkeys

x + y =28 ---> 2x + 2y = 56

4x + 2y =96

2x = 40

x= 20

y = 8

There were 20 cows and 8 turkeys

Source(s): my brain - PinarLv 61 decade ago
C+T=28

4C+2T=96 (4C refers to 4 leg cows)

C=28-T

4(28-T)+2T=96

112-4T+2T=96

T=8

C+T=28

C-8=28

C=20

8 turkeys, 20 cows