factor this...?

64 a cube + 1

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  • 1 decade ago
    Favorite Answer

    You can use the following formula:

    x^3+y^3=(x+y)(x^2-xy+y^2) where x^3=64a^3 and y^3=1.

    So x=4a and y=1, now plug in.

    This factors to (4a+1)(16a^2-4a+1)

    Source(s): math teacher
  • 1 decade ago

    Do the math baby

  • 1 decade ago

    you can't factor it; it doesn't have an x.

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