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# Given: y + 5/ y^2+4y - 32 . What are the excluded values?

A. y = -5 and 4

B. y = 5 and 32

C. y = 4 and -8

D. none of the above

### 1 Answer

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- 1 decade agoFavorite Answer
I am assuming 2 things: 1 that by excluded values you mean values not in the domain of this function (ie, things that will make the denominator 0) and also that the denominator is y^2+4y-32.

If I have assumed correctly, then you need to solve the equation y^2+4y-32 to get the answer. This factors into (y-4)(y+8)=0 so y-4=0 or y+8=0 and you get y=4 or y=-8, so c is correct.

Source(s): math teacher

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